**StATS: ****Calculating probabilities involving correlated normal variables (June 4, 2007)**

Someone on EDSTAT-L asked about a problem involving differences of independent normal random variables. I am simplifying the problem a bit, but it essentially asked a question that was comparable to the following:

Suppose you have three independent standard normal random variables: A, B, and C. What is the probability that A is smaller than B by one or more units and A is also smaller than B by one or more units.

This is equivalent to calculating the following probability.

If you redefine X=A-B and Y=A-C, then this probability changes to

where X and Y are correlated normal random variables with covariance matrix

The density function represented by this pair of correlated normal random variables looks like the following:

Notice the classic image of a bell shaped curve, but now it is in three dimensions rather than two. Note also that the width of the bell curves varies with the widest bells along the line x=y and the narrowest bells perpendicular to the line x=y. The probability shown above is equivalent to integrating the following portion of the bell shaped curve:

R has a library for calculation of multivariate t and multivariate normal distributions. You can compute the probability in question using the following R code.

```
s <- matrix(c(2,1,1,2),nrow=2)
pmvnorm(upper=c(-1,-1),mean=c(0,0),sigma=s)
```

which produces a probability of 0.1132. The calculation you would use if X and Y were independent

```
s <- matrix(c(2,0,0,2),nrow=2)
pmvnorm(upper=c(-1,-1),mean=c(0,0),sigma=s)
```

produces an incorrect answer (0.0575), which you could also get by multiplying the probability that two independent normal random variables with mean 0 and variance 2 would be less than -1.

pnorm(-1,mean=0,sd=sqrt(2))^2

The moral of this story is that when two events are correlated, you can't just get a bivariate probability by multiplying the univariate probabilities.

This page was written by Steve Simon while working at Children's Mercy Hospital. Although I do not hold the copyright for this material, I am reproducing it here as a service, as it is no longer available on the Children's Mercy Hospital website. Need more information? I have a page with general help resources. You can also browse for pages similar to this one at Category: Probability concepts.